Theoretical principles to improve power factor: Difference between revisions

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Improving the power factor of an installation requires a bank of capacitors which acts as a source of reactive energy. This arrangement is said to provide reactive energy compensation}}


{{Highlightbox|
An inductive load having a low power factor requires the generators and transmission/distribution systems to pass reactive current (lagging the system voltage by 90 degrees) with associated power losses and exaggerated voltage drops, as noted in [[The nature of reactive power ]]. If a bank of shunt capacitors is added to the load, its (capacitive) reactive current will take the same path through the power system as that of the load reactive current. Since, as pointed out in [[The nature of reactive power ]], this capacitive current Ic (which leads the system voltage by 90 degrees) is in direct phase opposition to the load reactive current (IL). The two components flowing through the same path will cancel each other, such that if the capacitor bank is sufficiently large and I<sub>C</sub> = I<sub>L</sub>, there will be no reactive current flow in the system upstream of the capacitors.
Improving the power factor of an installation requires a bank of capacitors which acts as a source of reactive energy. This arrangement is said to provide reactive energy compensation
 
}}
This is indicated in {{FigureRef|L9}} '''(a)''' and '''(b)''' which show the flow of the reactive components of current only.
 
In this figure:


An inductive load having a low power factor requires the generators and transmission/distribution systems to pass reactive current (lagging the system voltage by 90 degrees) with associated power losses and exaggerated voltage drops, as noted in sub-clause 1.3. If a bank of shunt capacitors is added to the load, its (capacitive) reactive current will take the same path through the power system as that of the load reactive current. Since, as pointed out in sub-clause 1.3, this capacitive current Ic (which leads the system voltage by 90 degrees) is in direct phase opposition to the load reactive current (IL). The two components flowing through the same path will cancel each other, such that if the capacitor bank is sufficiently large and Ic = IL, there will be no reactive current flow in the system upstream of the capacitors.<br>This is indicated in {{FigureRef|L8}} '''(a)''' and '''(b)''' which show the flow of the reactive components of current only.<br>In this figure:<br>R represents the active-power elements of the load<br>L represents the (inductive) reactive-power elements of the load<br>C represents the (capacitive) reactive-power elements of the power-factor correction equipment (i.e. capacitors).
R represents the active-power elements of the load


a) Reactive current components only flow pattern
L represents the (inductive) reactive-power elements of the load


[[File:FigL08a.jpg|none]]
C represents the (capacitive) reactive-power elements of the power-factor correction equipment (i.e. capacitors).
b) When IC = IL, all reactive power is supplied from the capacitor bank


[[File:FigL08b.jpg|left]] <br><br><br><br><br><br>c) With load current added to case '''(b)''' <br>[[File:FigL08c.jpg|left]] <br><br><br><br><br><br>'''''Fig. L8:''' Showing the essential features of power-factor correction''
{{Gallery|L9|Showing the essential features of power-factor correction||
|DB422585_EN.svg|a|Reactive current components only flow pattern
|DB422586_EN.svg|b|When I<sub>C</sub> {{=}} I<sub>L</sub>, all reactive power is supplied from the capacitor bank
|DB422587_EN.svg|c|With load current added to case '''(b)'''}}


It will be seen from diagram '''(b)''' of {{FigureRef|L9}}, that the capacitor bank C appears to be supplying all the reactive current of the load. For this reason, capacitors are sometimes referred to as “generators of leading vars”.  
It will be seen from diagram '''(b)''' of {{FigureRef|L9}}, that the capacitor bank C appears to be supplying all the reactive current of the load. For this reason, capacitors are sometimes referred to as “generators of leading vars”.  


In diagram '''(c)''' of {{FigureRef|L9}}, the active-power current component has been added, and shows that the (fully-compensated) load appears to the power system as having a power factor of 1.<br>In general, it is not economical to fully compensate an installation.
In diagram '''(c)''' of {{FigureRef|L9}}, the active-power current component has been added, and shows that the (fully-compensated) load appears to the power system as having a power factor of 1.
 
In general, it is not economical to fully compensate an installation.
 
{{FigureRef|L10}} uses the power diagram discussed in [[Definition of reactive power]] (see {{FigureRef|L2}}) to illustrate the principle of compensation by reducing a large reactive power Q to a smaller value Q’ by means of a bank of capacitors having a reactive power Qc.
 
In doing so, the magnitude of the apparent power S is seen reduced to S’.
 
Qc can be calculated by the following formula deduced from {{FigureRef|L10}}:
 
Qc=P.(tan(φ)-tan(φ'))


{{FigureRef|L9}} uses the power diagram ('''see Fig. L2''') to illustrate the principle of compensation by reducing a large reactive power Q to a smaller value Q’ by means of a bank of capacitors having a reactive power Qc. <br>In doing so, the magnitude of the apparent power S is seen reduced to S’.
{{FigImage|DB422588|svg|L10|Diagram showing the principle of compensationQc {{=}} P (tan φ - tan φ’)}}


Qc can be calculated by the following formula deduced from {{FigureRef|L9}}:
''' Example:'''


Qc=P.(tan(ϕ)-tan(ϕ'))
A motor consumes 100 kW at a power factor of 0.75 (i.e. tan φ = 0.88). To improve the power factor to 0.93 (i.e. tan φ = 0.4), the reactive power of the capacitor bank must be:


[[File:FigL09.jpg|none]]
Qc = 100 (0.88 - 0.4) = 48 kvar
'''''Fig. L9:''' Diagram showing the principle of compensation: Qc = P (tan ϕ - tan ϕ’)''


'''Example:<br>'''A motor consumes 100 kW at a power factor of 0.75 (i.e. tan ϕ = 0.88). To improve the power factor to 0.93 (i.e. tan ϕ = 0.4), the reactive power of the capacitor bank must be&nbsp;: Qc = 100 (0.88 - 0.4) = 48 kvar<br>The selected level of compensation and the calculation of rating for the capacitor bank depend on the particular installation. The factors requiring attention are explained in a general way in clause 5, and in clauses 6 and 7 for transformers and motors.  
The selected level of compensation and the calculation of rating for the capacitor bank depend on the particular installation. The factors requiring attention are explained in a general way in clause 5, and in clauses 6 and 7 for transformers and motors.  


'''Note:''' Before starting a compensation project, a number of precautions should be observed. In particular, oversizing of motors should be avoided, as well as the no-load running of motors. In this latter condition, the reactive energy consumed by a motor results in a very low power factor (≈ 0.17); this is because the kW taken by the motor (when it is unloaded) are very small.<br>
'''Note:'''  


[[ru:Теоретические принципы повышения коэффициента мощности]]
Before starting a compensation project, a number of precautions should be observed. In particular, oversizing of motors should be avoided, as well as the no-load running of motors. In this latter condition, the reactive energy consumed by a motor results in a very low power factor (≈ 0.17); this is because the kW taken by the motor (when it is unloaded) are very small.
[[zh:提高功率因数的原理]]

Latest revision as of 07:33, 4 August 2022

Improving the power factor of an installation requires a bank of capacitors which acts as a source of reactive energy. This arrangement is said to provide reactive energy compensation

An inductive load having a low power factor requires the generators and transmission/distribution systems to pass reactive current (lagging the system voltage by 90 degrees) with associated power losses and exaggerated voltage drops, as noted in The nature of reactive power . If a bank of shunt capacitors is added to the load, its (capacitive) reactive current will take the same path through the power system as that of the load reactive current. Since, as pointed out in The nature of reactive power , this capacitive current Ic (which leads the system voltage by 90 degrees) is in direct phase opposition to the load reactive current (IL). The two components flowing through the same path will cancel each other, such that if the capacitor bank is sufficiently large and IC = IL, there will be no reactive current flow in the system upstream of the capacitors.

This is indicated in Figure L9 (a) and (b) which show the flow of the reactive components of current only.

In this figure:

R represents the active-power elements of the load

L represents the (inductive) reactive-power elements of the load

C represents the (capacitive) reactive-power elements of the power-factor correction equipment (i.e. capacitors).

It will be seen from diagram (b) of Figure L9, that the capacitor bank C appears to be supplying all the reactive current of the load. For this reason, capacitors are sometimes referred to as “generators of leading vars”.

In diagram (c) of Figure L9, the active-power current component has been added, and shows that the (fully-compensated) load appears to the power system as having a power factor of 1.

In general, it is not economical to fully compensate an installation.

Figure L10 uses the power diagram discussed in Definition of reactive power (see Figure L2) to illustrate the principle of compensation by reducing a large reactive power Q to a smaller value Q’ by means of a bank of capacitors having a reactive power Qc.

In doing so, the magnitude of the apparent power S is seen reduced to S’.

Qc can be calculated by the following formula deduced from Figure L10:

Qc=P.(tan(φ)-tan(φ'))

Fig. L10 – Diagram showing the principle of compensation: Qc = P (tan φ - tan φ’)

Example:

A motor consumes 100 kW at a power factor of 0.75 (i.e. tan φ = 0.88). To improve the power factor to 0.93 (i.e. tan φ = 0.4), the reactive power of the capacitor bank must be:

Qc = 100 (0.88 - 0.4) = 48 kvar

The selected level of compensation and the calculation of rating for the capacitor bank depend on the particular installation. The factors requiring attention are explained in a general way in clause 5, and in clauses 6 and 7 for transformers and motors.

Note:

Before starting a compensation project, a number of precautions should be observed. In particular, oversizing of motors should be avoided, as well as the no-load running of motors. In this latter condition, the reactive energy consumed by a motor results in a very low power factor (≈ 0.17); this is because the kW taken by the motor (when it is unloaded) are very small.

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